x^2-22x+160=0

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Solution for x^2-22x+160=0 equation:


Simplifying
x2 + -22x + 160 = 0

Reorder the terms:
160 + -22x + x2 = 0

Solving
160 + -22x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-160' to each side of the equation.
160 + -22x + -160 + x2 = 0 + -160

Reorder the terms:
160 + -160 + -22x + x2 = 0 + -160

Combine like terms: 160 + -160 = 0
0 + -22x + x2 = 0 + -160
-22x + x2 = 0 + -160

Combine like terms: 0 + -160 = -160
-22x + x2 = -160

The x term is -22x.  Take half its coefficient (-11).
Square it (121) and add it to both sides.

Add '121' to each side of the equation.
-22x + 121 + x2 = -160 + 121

Reorder the terms:
121 + -22x + x2 = -160 + 121

Combine like terms: -160 + 121 = -39
121 + -22x + x2 = -39

Factor a perfect square on the left side:
(x + -11)(x + -11) = -39

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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